f(x)=[2/3x]

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Solution for f(x)=[2/3x] equation: 


sin(((1/2)*pi*i*x)/l)

sin((pi*i*x)/(2*l))

2-(p/5) = 1/4

(((((x^2)/3)*y^-4)/5)^1)/2 = 0

cos(ln(5*x^2))

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